May 12, 2015 · The square root of i is (1 + i)/sqrt (2). [Try it out my multiplying it by itself.] It has no special notation beyond other complex numbers; in my discipline, at least, it comes up about half as …

Apr 12, 2011 · Yes, just make sure you make sure you understand the distinctions below: $\frac {2} {\sqrt2}$ is obtained by multiplying the $\sqrt2$ by 1 or $\frac {\sqrt2} {\sqrt2}$. $$\left (\frac {\sqrt2} …

Nov 12, 2016 · What would be the derivative of square roots? For example if I have $2 \\sqrt{x}$ or $\\sqrt{x}$. I'm unsure how to find the derivative of these and include them especially in something …

Jan 16, 2015 · I'm trying to figure Taylor series for $\sqrt {x}$. Unfortunately all web pages and books show examples for $\sqrt {x+1}$. Is there any particular reason no one shows Taylor series for …

Jul 22, 2017 · $\sqrt {\cdot}$ is seen in most cases as a function in $ [0,\infty)$, so it have a unique value associated to each non-negative real. In this tradition we generally define $i:=\sqrt {-1}$, that can be …

If you want the negative square root, that would be $-\sqrt {4} = -2$. Both $-2$ and $2$ are square roots of $4$, but the notation $\sqrt {4}$ corresponds to only the positive square root.

Jun 24, 2014 · The square root of the square root of x is therefore $$\sqrt {\sqrt x} = (\sqrt x)^ {1/2} = (x^ {1/2})^ {1/2} = x^ {1/4} = \sqrt [\large 4] x$$ Since the domain of $\sqrt x$ is $ [0, + \infty)$, this is also …

This seems to be very little different than the standard notation for $\sqrt {4} = 2$ as opposed to $\sqrt {4} = -2$. By convention, we have a concept of a principal branch of the square root.

Method 1: $$\sqrt2=\sqrt {1+1}=1+\frac12-\frac18+\dots\approx1+\frac12-\frac18=\frac {11}8=1.375$$ which is much clearer to me, since it avoids having to take decimals raised to powers and gives you …

Feb 18, 2015 · So our teacher doesnt use the same demonstration as most other sites use for proving that gamma of a half is the square root of pi. I dont understand the demonstration from the first step …