Then, we can just find the mass of 2.272 carbon atoms by multiplying 2.272 by the mass of 1 mole of carbon: 2.272 xx 12.01 = "27.29g" Since there was 1 significant figure in the question, our answer is …

Explanation: #M_ (CO_2) = "220 mg"# #MW_ (CO_2) = "44.01 g/mol"# #"O"_2 " molecules = ?"#

How many #"g"# of water are required to be mixed with #"11.75 g"# of #HgCl# in order to make a #"0.01 m"# solution? How would you prepare 250. mL of a 0.175 M solution of Cobalt (II) Chloride from the …

18.01 ⋅ g ⋅ mol−1 6.022 ×1023 ⋅ mol−1 = 2.99 × 10−23 ⋅ g And if I were to add the individual atomic masses of 2 × H and 1 × O, of course I would get this mass.

14.33"g of "H_2O Here is your balanced equation: C_6H_12O_6+ 6O_2rarr 6H_2O+6C0_2 We start Dimensional analysis (the factor-label method) by writing the given information over 1: (35"g of …

"CO"_2 The question essentially wants you to figure out the molar mass, i.e. the mass of exactly 1 mole, of this compound. Now, the important thing to keep in mind here is that 1 mole of a molecular …

Nov 22, 2015 · "27 g" The trick here is to look out for the phase change underwent by the ice sample. More specifically, the ice will absorb heat from the hot water to go from solid at 0^@"C" to liquid at …

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Jun 4, 2018 · We address the combustion reaction.... C (CH_3)_4 (g) + 8O_2 (g) rarr 5CO_2 (g) +6H_2O (l) We specify a molar quantity WITH RESPECT TO WATER of.. (27.01*g)/ (18.01*g*mol^ …

0.56 1 molar solution ="Number of moles of solute"/"Volume of solution" for Sugar C_ (12)H_ (22)O_ (11) molar mass=342gm according to equation and information provided 1= (3.42/342)/x where x is …